Comments for puzzlewocky

Comment on Classic Short Brain Teasers and Riddles by Tom

Tom — Tue, 28 Jan 2025 16:01:04 +0000

Love these!!! Tysm!! Anymore good ones?

Comment on The Two Dice Wager by PeterW.

PeterW. — Tue, 28 Jan 2025 13:32:24 +0000

For those who disagree with the answer provided:
Would you care to “put your money where your mouth is”?
If you’ll commit to 100 throws of the dice, let’s play for $100 per throw!
Obviously, whichever of us has the most money at the end wins!

For my part, I just hate it when I’m wrong at the top of my lungs

Comment on A Collection of Short Paradoxes by Randy

Randy — Mon, 13 Jan 2025 17:21:14 +0000

I believe Parodox is a confusing statement that makes you think about if something is true or not.

Comment on The Wason Selection Task by Chris

Chris — Tue, 30 Jan 2024 06:23:19 +0000

In reply to Zack. It doesn’t disprove the statement. It says if ONE card has an even number then its reverse will be green. If either the green or the 8 has a reverse that makes the statement true, then it does not matter about the blue. The rule says nothing about the blue card.

Comment on The Wason Selection Task by Zack

Zack — Mon, 29 Jan 2024 18:43:11 +0000

In reply to Toferino. But if you turn over the blue card and it has an even number, then it disproves the statement, even if the 8 and green cards support the statement.

Comment on Stereograms by Andrej Olejnik

Andrej Olejnik — Sat, 27 Jan 2024 18:30:33 +0000

First 2 stereograms are from aolej.com web site (textures/depth maps) as part of Stereogram Explorer installation. Check easy stereograms for beginners – https://www.aolej.com/easy-stereograms-for-beginners

Comment on Stereograms by Andrej Olejnik

Andrej Olejnik — Sat, 27 Jan 2024 16:34:07 +0000

Check perfect clear parallel view stereograms

Comment on Stereograms by jomal

jomal — Tue, 09 Jan 2024 18:26:07 +0000

I could not see any of these. are they real?

Comment on Stereograms by Kyle

Kyle — Fri, 15 Dec 2023 20:03:52 +0000

In reply to NoooBady. This did it for me. One thing to keep in mind is that your eyes may not be perfectly level. once I realized this I tilted my head to compensate and saw it.

Comment on Boys and Girls Problems by EVERVONO

EVERVONO — Mon, 20 Nov 2023 18:49:52 +0000

In reply to EVERVONO. **Replying to my comment since I can't figure out how to edit it** Mistake no2 is nonsense, I take that back. For anyone else like me who struggles to understand how older/younger can provide extra information, I think its easier to understand if you categorize in terms of child 1 and child 2. I.e. the 4 possible ways to construct the two children in terms of child 1 and 2 is b,b or b,g or g,b or g,g . The condition in the first question can be rephrased to, "child 1 is a boy" and the condition in the second question to "either child 1 or child 2 is a boy". It is more clear to me this way how the first question is more selective and hence results in a larger probability. And then of course you can just change child 1 and child 2 to any arbitrary categories and the question still works. Basically, using the category of age is nice as a confusing smokescreen to make the question more interesting. That being said, mistake no1 applies. The solutions to questions 1 and 2 are different from what I originally wrote since I should have used P(A|D) and P(B|D) which are not both 1/2. Condition D is for question 1, the oldest child is a boy and for question 2, at least one child isa a boy. Question 1 had its solution prior to the observation of the boy with his father being 1/2 according to condition D. Thus the answer is still 2/3 as I wrote in my first post (correct by fluke). Question 2 has P(A) = 1/3 and P(B) = 2/3 (I'm skipping condition D and just writing P(A|D) as P(A) ). P(C) = P(A)*P(C|A) + P(B) * P(C|B) = 1/3 * 1 + 1/2 * 2/3 = 2/3 Thus, P(A|C) = P(A)*P(C|A)/ P(C) -> P(A|C) = (1/3) / (2/3) = 1/2. So looking back, I agree with what Nathan posted!